Math, asked by premchandp399, 4 hours ago

The ratio of present ages of two girls is 4:5. Five years ago, the ratio of their ages was 1:2. Find their present ages

Answers

Answered by NITESH761
8

Step-by-step explanation:

\Large\mathsf{\underline{Given:-}}

  • Ratio of their persent ages= 4:5
  • Ratio of their ages 5 years ago= 1:2

\Large\mathsf{\underline{To\:Find:-}}

  • Their present ages= ?

\Large\mathsf{\underline{Solution:-}}

Let their present ages be 4x and 5x

5 years ago:-

The ratio of their ages was 1:2

Let their ages be x and 2x

5 years later:-

x/2x+5 = 4x/5x

Now we have to solve this,

=> x/2x - 4x/5x = -5

=> (5x²-8x²)/10x² = -5

=> -3x²/10x² = -5

=> -3/10× x²/x² = -5

=> x²/x² = -5 × 10/(-3)

=> x² = -50x²/-3

=> -3x² = -59x²

Dear student,

There are no solutions for x because,

let x² be a

=> -3a = -59a

Here, how a times -3 is equal to a times -59 ?

There is a contradiction.

If we multiply a number with some quantity it will never be equal if we multiply that number with some other quantity

Here,

-3a always equal to -3a it will never be equal to -59a

Hope you understand

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