Math, asked by guleriasushmita6, 2 months ago

The ratio of present ages of two sisters is 1 : 2
and six years back the ratio was 1 : 3. What will
be the ratio of the ages after six years-
(a) 35
(b) 5:3
(c) 2:3
(d) 3:2
7. Vinu can do a piece of work in 7 days of 9 hours
each and Meenu can do it in 6 ways of 7 hours
each. How long will they take to do it working​

Answers

Answered by gouthamraju389
1

Answer:

Step-by-step explanation:

Let the ages of the sisters be x and 2x respectively, where x is any constant.

1st sister's age 6 years back = x - 6

2nd sister's age 6 years back = 2x - 6

( x - 6 ) / ( 2x - 6 ) = 1 / 3

3x - 18 = 2x - 6

3x - 2x = -6 + 18

x = 12

1st sister age after 6 years = 12 + 6 = 18 years

2nd sister age after 6 years = 24 + 6 = 30 years

Therefore, ratio = 18 / 30

= 3:5

Hope this helps you

Have a nice day :)

Answered by rusandi
0

Step-by-step explanation:

Q01.

present ages: x and 2x

six years back: x-6, 2x-6

\frac{x-6}{2x-6}=\frac{1}{3}  \\\\3x-18=2x-6\\\\x=12\\\\after\ six \ years :\\\\\frac{x+6}{2x+6} =\frac{18}{30} =\frac{3}{5}

Q02.

Vinu = 63 hours

Meenu = 42 hours

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