Question

the ratio of Rates of diffusion of a SO2 O2 and ch4 under identical conditions is

Answer 1

According to the law of diffusion :

Under same condition of temperature and pressure, rate of diffusion of gases is inversely proportional to square root of their masses .

Molar masses of different gases:

SO₂=64

O₂=32

CH₄= 16

Their rate of diffusion is as follows:

$r_{SO_{2}}=\frac{1}{\sqrt{64}}$

$r_{O_{2}}=\frac{1}{\sqrt{32}}$

$r_{CH_{4}}=\frac{1}{\sqrt{16}}$

Ratio of rate of diffusion:

$r_{SO_{2}} : r_{O_{2}} : r_{CH_{4}} = 1 :\sqrt{2} :2$

Answer 2

The answer is 

                       1 :  : 2

 

    As according to GRAHAM’s LAW;

                          

      So for SO2;

                     M = 64

                     R1 = 1/8

 

             For O2;

                     M = 32

                     R2 = 4

                

               For CH4;

                    M = 16

                    R3 = 4   

 

       SO,

            R1 : R2 : R3 = 1 :  : 2