Question

the ratio of root mean square value and peak value of an alternating current is

Answer 1

The ratio of root mean square value and peak value of an alternating current is

Answer 2

when the equation of current of an alternating current is given by, $I=I_0sin(\omega t+\phi)$

then, $I_0$is the peak value of the alternating current.

relation between root mean square value of alternating current and peak value of current is given by, $I_{rms}=\frac{I_0}{\sqrt{2}}$

where $I_{rms}$ denotes rms value of an alternating current.

so, the ratio of root mean square value and peak value of an alternating current is $\frac{I_{rms}}{I_0}=\frac{I_0}{\sqrt{2}I_0}=\frac{1}{\sqrt{2}}$

hence, 1 : √2 is the answer.