Question

The ratio of secondary to primary turns is 4:5. if power input is p, what will be the ratio of power output (neglect all losses) to power input ?

Answer 1

Hello Dear.

Here is the answer---

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Given ⇒

N(p)/N(s)= 4 : 5

∵ N(p)/N(s) = Ep/Es
 ∴ E(p)/E(s) = 4/5

⇒ E(s) = 5/4  × E(p)



 Power Input = p
⇒ E(p) × I(p) = p

Power Output = E(s) × I(s)

If all the loses are neglected, then

    Power Input = Power Output 
⇒ E(p) × I(p) = E(s) × I(s)
⇒ $\frac{Ep}{Es} = \frac{Is}{Ip}$
⇒    I(s)/I(p) = 4/5
⇒ I(s) = 4/5 × I(p)


Thus, power Output = E(s) × I(s)
                                 = (5/4) × E(p) × (4/5) × I(p)
                                 = E(p) × I(p)
                                 = p

∴ Ratio of the Power Output to the Power Input = p/p
   = 1 : 1



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Hope it helps.


Have a Nice Day.