Math, asked by bhuvabeshwarirathore, 5 months ago

The ratio of surface areas of 1 cube of
volume 64 cm and 64 cubes of volume
1​

Answers

Answered by Anonymous
11

Answer:

SOLUTION

Let us call the cube of volume 64 cm3 as cube A and the cube with volume 1 cm3 as cube B.

Length of side of cube A =3√64=4 cm

Surface area of cube A =6×(4)2=96 cm2

Length of side of cube B =1 cm

Surface area of a cube of side 1 cm  6l2=6(1)2=6 cm2

Therefore surface area of 64 such cubes =64×6=3842

Ratio of surface areas = 96:384

⇒1:4

Step-by-step explanation:

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