Question

The ratio of the ages of a and b at present is 4:3 10 years earlier the ratio was 3:2, then find the present ages of a and b

Answer 1

Step-by-step explanation:

let ratio of present age = 4x:3x

according to question

10 year earlier its ratio was 3:2

so, 4x-10 / 3x-10 = 3:2

after cross multiplying and solving the equation we get x = 10

so the present age are 40 years,30 years respectively.

Answer 2

Given,

The ratio of present ages of a and b is 4:3.

10 years before the ratio of their ages was 3:2.

To Find,

The present age of a and b.

Solution,

As given the ratio of present ages of a and b is 4:3.

Suppose the present age of a and b is 4x and 3x.

10 years ago the age of a was 4x-10 and the age of a was 3x-10.

Given that 10 years before the ratio of their ages was 3:2.

So we can say, $\frac{4x-10}{3x-10} =\frac{3}{2}$.

⇒2×(4x-10)=3×(3x-10).

⇒8x-20=9x-30.

⇒9x-8x=+30-20.

⇒x=10.

The present age of a is 4x =4×10=40.

the present age of b is 3x =3×10=30.

Hence, the present ages of a and b are 40years and 30years respectively.