Math, asked by vipritk2009, 9 days ago

the ratio of the ages of a father and his son is 17 :7 .6 years ago the ratio of their ages was 3 : 1 the father's present age is please jaldi batao​

Answers

Answered by XxMissReporterxX01
26

The ratio of the ages of a father and son is 17:7, respectively.

Six years ago the ratio of their ages was 3:1, respectively.

What is the son's present age?

(Answer: 21 years)

Answered by MathCracker
10

Question :-

the ratio of the ages of a father and his son is 17 :7 .6 years ago the ratio of their ages was 3 : 1 the father's present age is ?

Answer :-

  • Father's present age is 51yrs.

Step by step explanation :-

Let,

The father's present age will be 17x,

And the present age of son's will be 7x.

We have given that,

6 years ago the ratio of their ages was 3 : 1 .

As can be written as,

\rm:\longmapsto{ \frac{17x - 6}{7x - 6} =  \frac{3}{1}  } \\

Now, we find the value of x.

\rm:\longmapsto{1(17x - 6) = 3(7x - 6)} \\  \\ \rm:\longmapsto{17x  - 6 = 21x - 18} \:  \:  \:  \:  \:  \:  \\  \\ \rm:\longmapsto{21x - 17x =  - 6 + 18} \:  \:  \\  \\ \rm:\longmapsto{4x = 12} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \rm:\longmapsto{x =  \frac{12}{4} } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \rm:\longmapsto \red{x = 3} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

Now,

The father's present age is :

➵ 17x

➵ 17(3)

➵ 51

The father's present age is 51years.

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