Math, asked by nishchhal79, 9 months ago

The ratio of the ages of a father and his son is17:7.Six years ago the ratio was 3:1. The father's present age is​

Answers

Answered by uthirasreemurugadoss
4

Answer:51 yrs

Step-by-step explanation:

Let the present age of father and son be 17x years and 7x years respectively.  

According to the question. 17x -6 _ 3  

17x−67x−6=31

=> 21x - 18 = 17x - 6  

=> 21x - 17x = 18 - 6  

=> 4x = 12  

=> x = 124 = 3

Therefore, Father's present age = 17×3 = 51 years

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