The ratio of the ages of neeti & yash is 4 : 3, the sum of their ages is 28 yrs. What is the ratio of their ages after eight years?
Answers
Step-by-step explanation:
let the common ratio be x.
neeti age = 4x
yash age= 3x
According to the question,
neeti age + yash age= 28
4x+3x = 28
7x=28
x=28/7
x=4
age of neeti = 4x= 4*4=16
age of yash= 3x= 3*4=12
after 8 years
neeti age =16+8= 24
yash age=12+8= 20
ratio of their ages,
neeti age/yash age = 24/20
=6/5
neeti age : yash age = 6:5
Step-by-step explanation:
Let the present Ages be -
Neeti as 4x
Yash as 3x
➠ 4x + 3x = 28
➠ 7x = 28
➠ x = 28/7
➠ x = 4
\rule{300}{1.5}
Neeti's present age =
➠ 4 × 4
➠ 16
Neeti = 16 years old
\rule{300}{1.5}
Yash's present age =
➠ 3 × 4
➠ 12
Yash = 12 years old
\rule{300}{1.5}
Ages after 8 years =
➠ Neeti = 16 + 8 = 24 years
➠ Yash = 12 + 8 = 20 years
\rule{300}{1.5}
Ratio of their Ages =
➠ Neeti/Yash
➠ 24/20
➠ 6/5
➠ 6 : 5
\therefore∴ The ratio of Ages after 8 years is 6 : 5.