The ratio of the ages of two sisters is 3:7. in ten years, the ratio of their ages become 2:3.find their present ages
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Answered by
9
hola mate,
let the age of the first sister be 3x
and the age of second sister be 7x
after 10 years,
first sisters age=3x+10
second sisters age=7x+10
3x+10/7x+10=2:3
3x+10/7x+10=2/3
3(3x+10)=2(7x+10)
9x+30=14x+20
9x-14x=20-30
-5x= -10
x= -10/-5
x=2
hence,
first sisters present age = 3x=3*2=6 years
second sisters present age = 7x=7*2=14 years.
hope you understand my process.
if any query please ask.
thanks for asking this question.
hope it works
let the age of the first sister be 3x
and the age of second sister be 7x
after 10 years,
first sisters age=3x+10
second sisters age=7x+10
3x+10/7x+10=2:3
3x+10/7x+10=2/3
3(3x+10)=2(7x+10)
9x+30=14x+20
9x-14x=20-30
-5x= -10
x= -10/-5
x=2
hence,
first sisters present age = 3x=3*2=6 years
second sisters present age = 7x=7*2=14 years.
hope you understand my process.
if any query please ask.
thanks for asking this question.
hope it works
Answered by
2
Answer:
Answer is 6 and 14 years
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