Question

the ratio of the area of the sinusoidal waveform over a half cycle to the time period of half cycle is ?​

Answer 1

Explanation:

hope it will help you bro

Answer 2

Answer:

Required ratio is $\frac{2 \sqrt{2} }{\pi}$

Explanation:

The mean or average value of AC waves is taken to be 0 since the negative and positive parts cancel each other and give us zero. But, if we consider half cycle of ac, we get the mean value or average value of a half cycle of ac wave as:

$V_{avg}=2 \frac{V_{peak}}{\pi}$

Where,$V_{avg}$is the average value of voltage.

Vpeak is the peak value of voltage.

The r.m.s value of an ac signal for half cycle is given as:

$V_{rms}= \frac{V_{peak}}{ \sqrt{2} }$

The ratio of mean value to rms value over half cycle of an ac is given as follows:

The ratio of mean value to rms value over half cycle of ac is $\frac{2 \sqrt{2} }{\pi}$

Additional Information:

Alternating current or ac is defined as the current whose magnitude and direction changes with time. The mean value of ac cycle is 0 so the rms value is considered to study the behavioral changes or trends in the current flow.