the ratio of the area of two triangle is 4:3 and the ratio of their height 3:4 find the ratio of the base
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Answered by
7
Let the bases of the two triangles be x and y and their heights be 3h and 4h respectively.
Then,((1/2) X x X 3h)/(1/2) X y X 4h)
=4/3 =x/y
=(4/3 X 4/3)
=16/9
Required ratio = 16 : 9.
Then,((1/2) X x X 3h)/(1/2) X y X 4h)
=4/3 =x/y
=(4/3 X 4/3)
=16/9
Required ratio = 16 : 9.
Answered by
5
Answer:
Step-by-step explanation:Let the heights of the two triangles are 3x and 4x
Let the bases of the two triangles are p and q respectively.
We know that, area of the triangle = ×base×height
Ratio of areas = 4 : 3
× p ×3x : × q × 4x = 4 : 3
3px : 4qx = 4 : 3
Product of extremes = product of means
9px = 16qx
p/q = 16/ 9
p : q = 16 : 9
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