Question

The ratio of the areas of two square, where the digonal of ine square is twice the length of the other is

Answer 1

Let the diagonal of first square be a

Diagonal of second square = 2a

Side of first square = a / root2

Area of first square = a^2 /2

A1 = a^2 /2


Side of second square = 2a/ root2

A2 = 4a^2 /2

A2 = 2a^2


A1 : A2 = 1 : 4

Answer 2

Let the diagonal of first square be a

Diagonal of second square = 2a

Side of first square = a / root2

Area of first square = a^2 /2

A1 = a^2 /2

Side of second square = 2a/ root2

A2 = 4a^2 /2

A2 = 2a^2

A1 : A2 = 1 : 4

hope it helped ⚡

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