Math, asked by 2002yomali, 2 months ago

The ratio of the boys to girls in a school is 3 : 5. If the total number of students in the school is 1800, find the number of boys and girls in the school

Answers

Answered by MagicalBeast
6

Given :

  • Boys : Girls = 3:5
  • Total number of students = 1800

Let :

  • Number of boys = x
  • Number of girls = y

To find :

  • Number of boys
  • Number of girls

Solution :

 \sf \: x  : y \:  =  \:3 : 5 \\  \\  \sf \implies \:  \dfrac{x}{y}  =  \dfrac{3}{5}  \\  \sf \implies \: x \:  =  \dfrac{3}{5} y \: ..........equation1

Also,

x + y = 1800

Putting value of x from equation 1, we get;

 \sf \implies  \dfrac{3}{5} y \:  + y = 1800 \\  \\  \sf \implies \:  \frac{3 + (1 \times 5)}{5} y = 1800 \\  \\  \sf \implies \: 8y = 1800 \times 5 \\  \\  \sf \implies \: y \:  = 9000 \div 8 \\  \\  \sf \implies \: y = 1125

putting value of y in equation 1,

=> x = (3×1125)/5

=> x = 675

ANSWER :

  • Number of boys (x) = 675
  • Number of girls (y) = 1125

Answered by Anonymous
8

Given :

Boys : Girls = 3:5

Total number of students = 1800

Let :

Number of boys = x

Number of girls = y

To find :

Number of boys

Number of girls

\huge\underline\red{Solution:}

\begin{gathered} \sf \: x : y \: = \:3 : 5 \\ \\ \sf \implies \: \dfrac{x}{y} = \dfrac{3}{5} \\ \sf \implies \: x \: = \dfrac{3}{5} y \: ..........equation1\end{gathered}

Also,

x + y = 1800

1800Putting value of x from equation 1, we get;

\begin{gathered} \sf \implies \dfrac{3}{5} y \: + y = 1800 \\ \\ \sf \implies \: \frac{3 + (1 \times 5)}{5} y = 1800 \\ \\ \sf \implies \: 8y = 1800 \times 5 \\ \\ \sf \implies \: y \: = 9000 \div 8 \\ \\ \sf \implies \: y = 1125\end{gathered}

y=1800

8y=1800×5

y=9000÷8

y=1125

putting value of y in equation 1,

=> x = (3×1125)/5

=> x = 675

\huge\underline\purple{Answer:-}

Number of boys (x) = 675

Number of girls (y) = 1125

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