Question

The ratio of the diameters of a torus and mesh of dimensions 8 x sqrt(n) x (1/8 x sqrt(n)) is

Answer 1

"The ratio of the diameter of the torus and mesh of the dimension

diameter of the torus : mesh of the dimension

8 square root n : 1/8 square root n

Square root will cancel out square root

8 : 1/8

A divided by B/C = A * C divided by B

8 * 8 : 1

64 : 1

"