Question

the ratio of the difference in energy between the first and second bohr orbit to that between second and third orbit in H atom is

Answer 1

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Answer 2

Hey dear,

● Answer -
∆E21 : ∆E32 = 27 : 5

● Explanation -
Energy in nth Bohr orbit is given by -
En = -13.6 / n^2

Hence,
∆E21 = E2 - E1
∆E21 = (-13.6/2^2) - (-13.6/1^2)
∆E21 = 13.6 × (1-1/4)
∆E21= 13.6 (3/4)

Also,
∆E32 = E3 - E2
∆E32 = (-13.6/3^2) - (-13.6/2^2)
∆E32 = 13.6 × (1/4-1/9)
∆E32 = 13.6 (5/36)

Ratio of ∆E21 and E32 is -
∆E21/∆E32 = (13.6×3/4) / (13.6×5/36)
∆E21/∆E32 = 27/5


Hope this helps you...