Question

The ratio of the difference in energy of electron between the first and second Bohr's orbits to that
between second and third Bohr's orbits is:
(A) 1/3
(B) 27/5
(C) 9/4
(D) 4/9
​

Answer 1

Correct Answer:

27/5

Explanation:

E₁ – E₂ = 1312 x Z²(1/1² – 1/2²)

= 1312 x Z²(3/4)

E₂ – E₃ = 1312 x Z²(1/2² – 1/3²)

= 1312 x Z²(5/36)

From eqs. (i) and (ii)

E₁ – E₂ / E₂ – E₃ = 3 x 26 / 4 x 5 = 27/5

So option B is the right answer....

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