the ratio of the digit is 3-digit to the number 1:2:3 on adding 396 to the number its digit are reversed find the number
Answers
Answered by
11
Let the unit digit be 3x,tens digit be (2x) and hundreds digit be (x).
So, no. =100(x)+10(2x)+3x
According to question ..
100x+20x+3x+396=100(3x)+10(2x)+x
396=198x=>x=2.
So,no= 100(2)+10(4)+6
=246
So, no. =100(x)+10(2x)+3x
According to question ..
100x+20x+3x+396=100(3x)+10(2x)+x
396=198x=>x=2.
So,no= 100(2)+10(4)+6
=246
Answered by
20
Here is your solution
Given :-
Ratio x : y : z = 1 : 2 : 3
Let ,
The number be xyz.
3x = z , 2x = y .
A/q
100x+10y+z + 396 = 100z + 10y + x (given)
99x-99z = -396
99z - 99x = 396
z - x = 396/99
z - x = 4
3x - x = 4 .
2x = 4
x = 2
Hence,
The number is 246
hope it helps you
Given :-
Ratio x : y : z = 1 : 2 : 3
Let ,
The number be xyz.
3x = z , 2x = y .
A/q
100x+10y+z + 396 = 100z + 10y + x (given)
99x-99z = -396
99z - 99x = 396
z - x = 396/99
z - x = 4
3x - x = 4 .
2x = 4
x = 2
Hence,
The number is 246
hope it helps you
Similar questions