the ratio of the digit of a 3-digit number 1:2:3: on adding 396 to the number the digit are reversed find the number
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Answered by
6
Let the number be xyz.
Given ratio x : y : z = 1 : 2 : 3
So, 3x = z , 2x = y .
Also given,
100x+10y+z + 396 = 100z + 10y + x
99x-99z = -396
99z - 99x = 396
z - x = 396/99
z - x = 4
3x - x = 4 .
2x = 4
x = 2 .
So, the number is 246
Given ratio x : y : z = 1 : 2 : 3
So, 3x = z , 2x = y .
Also given,
100x+10y+z + 396 = 100z + 10y + x
99x-99z = -396
99z - 99x = 396
z - x = 396/99
z - x = 4
3x - x = 4 .
2x = 4
x = 2 .
So, the number is 246
Answered by
24
Here is your solution
Given :-
Ratio x : y : z = 1 : 2 : 3
Let ,
The number be xyz.
3x = z , 2x = y .
A/q
100x+10y+z + 396 = 100z + 10y + x (given)
99x-99z = -396
99z - 99x = 396
z - x = 396/99
z - x = 4
3x - x = 4 .
2x = 4
x = 2
Hence,
The number is 246
hope it helps you
Given :-
Ratio x : y : z = 1 : 2 : 3
Let ,
The number be xyz.
3x = z , 2x = y .
A/q
100x+10y+z + 396 = 100z + 10y + x (given)
99x-99z = -396
99z - 99x = 396
z - x = 396/99
z - x = 4
3x - x = 4 .
2x = 4
x = 2
Hence,
The number is 246
hope it helps you
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