Question

The ratio of the e/m values of a electron and an alpha particle is -?

Answer 1

For Electron:-

Charge= -1.602 × 10^-19 C

Mass= 9.109 × 10^-31 kg

Specific charge= charge/mass

= (-1.602×10^-19)/(9.109×10^-31) C/kg

= -1.758 × 10^11 C/kg

Specific charge of electron= -1.758 × 10^11 C/kg

For alpha particle:-

Charge= 3.2 × 10^-19 C

Mass= 6.644 × 10^-27 kg

Specific charge= Charge/mass

= (3.2 × 10^-19)/(6.644 × 10^-27) C/kg

= 4.816 × 10^7 C/kg

Specific charge of alpha particle= 4.816 × 10^7 C/kg

Ratio of specific charges = specific charge of electron÷specific charge of alpha particle

Ratio= (-1.758 × 10^11)/(4.816 × 10^7)

= -3.650 × 10^3

Therefore, the ratio of specific charges of electron and alpha particle is -3.650×10^3

Answer 2

Answer: The ratio of e/m values of electron and alpha particle is $-3.650\times 10^{3}$

Explanation:

We know that:

Charge of an electron = $-1.602\times 10^{-19}C$

Mass of an electron = $9.109\times 10^{-31}kg$

Charge of an alpha particle = $3.2\times 10^{-19}C$

Mass of an alpha particle = $6.644\times 10^{-27}kg$

To calculate the specific charge, we use the equation:

$\text{Specific charge of the particle}=\frac{\text{Charge of the particle}}{\text{Mass of the particle}}$

Specific charge of a electron = $\frac{(-1.602\times 10^{-19})}{(9.109\times 10^{-31})}C/kg=-1.758\times 10^{11}C/kg$

Specific charge of an alpha particle = $\frac{(3.2\times 10^{-19})}{(6.644\times 10^{-27})}C/kg=4.816\times 10^7C/kg$

Taking their ratios, we get:

$\frac{\text{Specific charge of electron}}{\text{Specific charge of alpha particle}}=\frac{-1.758\times 10^{11}C/kg}{4.816\times 10^7C/kg}=-3.650\times 10^3$

Hence, the ratio of e/m values of electron and alpha particle is $-3.650\times 10^{3}$