two supplementary angles are in ratio 3 ratio 2 find the angles
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Answered by
20
let one angle be x.
so the other one will be 180-x.
so,x/(180-x)=3/2
2x = 540-3x
x = 540/5 = 108
and the other one is 72
so the other one will be 180-x.
so,x/(180-x)=3/2
2x = 540-3x
x = 540/5 = 108
and the other one is 72
Answered by
21
Here we have ,
Two supplementary angles with ratio 2 and 3
Let the common ratio be x
Therefore , one angle is - 2x and 3x
Now the sum of two supplementary angles is equal to 180 degrees .
So , 2x +3x = 180degrees
5x = 180
X = 180 /5
X = 36degrees
Hence the measure of two equal angles is -
2x = 2 × 36 = 72 degrees
3x = 3 ×36 = 108 degrees
Two supplementary angles with ratio 2 and 3
Let the common ratio be x
Therefore , one angle is - 2x and 3x
Now the sum of two supplementary angles is equal to 180 degrees .
So , 2x +3x = 180degrees
5x = 180
X = 180 /5
X = 36degrees
Hence the measure of two equal angles is -
2x = 2 × 36 = 72 degrees
3x = 3 ×36 = 108 degrees
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