Question

The ratio of the efficiencies of a,b and c is 7:5:4. Working together, they can finish a work in 35 days, a and b work together for 28 days. The remaining work wikk be completed in days by c alone

Answer 1

Answer:

Construct a right angle triangle ABC,whose hypotenuse AC=5.2cm and sum of remaining two sides is 7.2cm

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Answer 2

The time taken to complete remaining work is 56 days.

Step-by-step explanation:

Consider the provided information.

The ratio of the efficiencies of a,b and c is 7:5:4.

So the number of days to finish a work by a, b and c are $\dfrac{x}{7} ,\dfrac{x}{5} \ and\ \dfrac{x}{4}$ respectively. Where x is the common factor.

Efficiency is inversely proportional to time taken.

If they can finish a work in 35 days.

$\dfrac{7}{x} +\dfrac{5}{x} +\dfrac{4}{x} =\dfrac{1}{35}$

$x=16\times35$

a and b work together for 28 days.

The work done by a and b in 28 days: $28\left(\dfrac{7}{x} +\dfrac{5}{x}\right) =\dfrac{12\times28}{x}$

Substitute the value of x.

$\dfrac{12\times28}{16\times35}=\dfrac{3}{5}$

A and B completed $\dfrac{3}{5}$ th of work now C need to complete only $\dfrac{2}{5}$ th of work.

C can do the work in $\frac{16\times35}{4}=140$ days.

Hence, the time taken to complete remaining work is $\frac{140\times2}{5} =56$ days.

#Learn more

A and B can do a given piece of work in 8 days B and C can do the same work in 12 days and a b c complete it in 6 days in how many days can A and C finish it​

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