The ratio of the energy required to remove an electron from the first three bhors orbit of hydrogen
Answers
Answered by
5
Energy required to remove electron from 1st Bohr Orbit of Hygrogen is
E = -13.6* Z^2/n^2
E = -13.6 ; 13.6
Energy required to remove electron from 2nd Bohr Orbit of H atom is
E = -13.6* Z^2/n^2
E = -13.6 / 4
Energy required to remove electron from 3nd Bohr Orbit of H atom is
E = -13.6* Z^2/n^2
E = -13.6 / 9
Ratio of 1st : 2nd : 3rd is
9:4:1
this is your answer
E = -13.6* Z^2/n^2
E = -13.6 ; 13.6
Energy required to remove electron from 2nd Bohr Orbit of H atom is
E = -13.6* Z^2/n^2
E = -13.6 / 4
Energy required to remove electron from 3nd Bohr Orbit of H atom is
E = -13.6* Z^2/n^2
E = -13.6 / 9
Ratio of 1st : 2nd : 3rd is
9:4:1
this is your answer
Answered by
2
Answer: 1:4:9
Explanation:
Attachments:
Similar questions