The ratio of the equal sides to the base of an isosceles triangle is 3:1. If the perimeter
of the triangle is 28 cm, then find its area."
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Answer:
4√35 cm²
Step-by-step explanation:
Let ABC be an isosceles triangle with perimeter 28 cm.
We have ratio of equal side to its base is 3:1.
Let sides of a triangle be AB = AC = 3x, BC = x
∴ Perimeter of triangle = 28 cm
⇒ 3x + 3x + x = 28
⇒ 7x = 28
⇒ x = 4 cm
∴ AB = AC = 3 * 4 = 12 cm
∴ BC = 4 cm
The sides of a triangle are,
a = 12 cm, b = 12 cm, c = 4 cm
S = (a + b + c)/2
= (12 + 12 + 4)/2
= 14 cm
∴ Area of an isosceles ΔABC,
= √s(s - a)(s - b)(s - c)
= √14(14 - 12)(14 - 12)(14 - 4)
= √14 * 2 * 2 * 10
= 4√35
Hence, area of an isosceles triangle = 4√35 cm²
Hope it helps!
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