Question

The ratio of the length of a parallel sides of a trapazium is 5:3 and the distance between them is 16cm. If the area of the trapazium is 960cm find the length of the parallel sides

Answer 1

Given that the ratio of the lengths of the parallel sides of a trapezium = 5 : 3

let the constant ratio be ' x '
now let the parallel sides of trapezium are 5x , 3x

Given, distance between the parallel sides of trapezium = 16 cm

and area of trapezium = 960 cm^2

since, we know that

area of trapezium
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= 1 / 2 ( sum of parallel sides )×distance between the parallel sides .

960 = 1/ 2 ( 5x + 3x ) × 16

960 = 8 x × 8

960 = 64x => x = 15

therefore ,

required lengths of the parallel sides are
5x = 5 × 15 = 75 cm

3x = 3 × 15 = 45 cm
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Your Answer : 75 cm , 45cm
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Answer 2

Given :

Ratios of parallel sides of the trapezium = 5:3

Altitude of trapezium = 16 cm

Area of the trapezium = 960 cm²

To Find :

The parallel sides of the trapezium.

Solution :

Let them in the form of x .

5x:3x

Now ,

Area of trapezium = 960 cm²

½×(sum of parallel sides)×altitude = 960

½×(5x+3x) × 16 = 960

½×8x×16 = 960

16×8x = 2×960

16×8 X = 1920

8x = 1920/16

8x = 120

X = 120/8

X= 15 cm

Now ,

5x = 5×15 = 75 cm

3x = 3×15 = 45 cm