Question

The ratio of the longest to shortest wavelengths in Brackett series of hydrogen spectra is(a) $\frac{25}{9}$(b) $\frac{17}{6}$(c) $\frac{9}{5}$(d) $\frac{4}{3}$

Answer 1

option (d) 4/3. do answer is that only

Answer 2

Answer:

a) 25/9

Explanation:

The Brackett series is defined by the equation - 1/λmax

Thus,

= R ( 1/4²-1/5²)

= 9/25×16 = R

whereas - 1/λmin

= R ( 1/4²- 1/∞²)

= R/16

= λmax/ λmin

= 25/9

Thus, the ratio of the longest to shortest wavelengths in Brackett series of hydrogen spectra is 25/9