The Ratio of the no. of boys to the no. of girls in a school of 560 pupils is 5:3 . If 10 new boys are admitted . find how many new girls may be admitted so that the ratio of the no. of boys to the no. of girls may change to 3:2
Answers
Answered by
40
5x+3x=560
x=70
boys=5x=350
girls=210
new no. of boys=10+350=360
let the no. girls added be y
360/210+y=3/2
y=30 ans
x=70
boys=5x=350
girls=210
new no. of boys=10+350=360
let the no. girls added be y
360/210+y=3/2
y=30 ans
maddy42:
30 kaise aaya
3(210+y)=2*360
y=240-210=30
tq frd
Answered by
21
5x+3x=560
8x=560
x=560/8
x=70
boys : 5x = 5X70=350
girls: 3x=3*70= 210
Now 10 new boys admitted
boys: 350+10=360
girls: 210+y
360:(210+y)=3:2
Product of extremely terms = Product of middle terms
360*2=(210+y)3
720=630+3y
3y=720-630
3y=90
y=90/3
y=30
new 30 girls are added
Total girls 210+30 =240
We can check the answer
360/240
which gives ratio 3:2
8x=560
x=560/8
x=70
boys : 5x = 5X70=350
girls: 3x=3*70= 210
Now 10 new boys admitted
boys: 350+10=360
girls: 210+y
360:(210+y)=3:2
Product of extremely terms = Product of middle terms
360*2=(210+y)3
720=630+3y
3y=720-630
3y=90
y=90/3
y=30
new 30 girls are added
Total girls 210+30 =240
We can check the answer
360/240
which gives ratio 3:2
check the correct answer
i have updated it again
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what is the true answer
30 is answer
Total girl is 240
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