Math, asked by shivajikokane, 5 months ago

the ratio of the present age of mother and her son is 2:1 . 6 year ago the ratio of their ages was 9:4 find the Mother's present age​

Answers

Answered by bson
8

Step-by-step explanation:

m:s = 2:1

m = 2s

m-6/s-6 = 9:4

4(2s-6 ) = 9(s-6)

8s - 24 = 9s -54

54-24 = s

s = 30

m= 30×2= 60

Answered by halamadrid
1

The mother's present age​ is 60 years.

Given:

The ratio of the present age of the mother and her son is 2:1.

6 years ago the ratio of their ages was 9:4.

To Find:

The mother's present age​.

Solution:

Let us assume that the mother's and the son's present ages are m years and s years respectively.

According to the given condition, the ratio of the present age of the mother and her son is 2:1.

⇒ m/s = 2/1

⇒ m = 2s     ....................(I)

Their ages 6 years ago:

The mother's age 6 years ago  = (m-6) years.

The son's age 6 years ago  = (s-6) years.

It is given that 6 years ago the ratio of their ages was 9:4.

⇒ (m-6)/(s-6) = 9/4.

⇒ (2s-6)/(s-6) = 9/4      ....................using (I)

⇒ 8s-24 = 9s-54

⇒ 9s-8s = 54-24 = 30.

⇒ s = 30

Hence, the son's present age s = 30 years.

So, m = 2s = 2(30) = 60.

Hence, the mother's present age m = 60 years.

∴ The mother's present age​ is 60 years.

#SPJ2.

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