the ratio of the present age of pawan and sushil is 7:2. after 8 years, the ratio of their ages will be 5:2. find the present age
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Answered by
7
let present age of pawan be 7x.
so , the present age of sushil is 2x.
now,
after 8 years , the age of pawan will be = 8+7x
while that of sushil = 8+2x
it is given that the ratio of their ages if 5 :2
so... 8 +7x /8+2x = 5 /2
so , x= 6 years
so present age of pawan = 7x = 7 * 6 =42
and that of sushil = 2x = 2 * 6 = 12...
thnx...maybe this is helpful.. :0
so , the present age of sushil is 2x.
now,
after 8 years , the age of pawan will be = 8+7x
while that of sushil = 8+2x
it is given that the ratio of their ages if 5 :2
so... 8 +7x /8+2x = 5 /2
so , x= 6 years
so present age of pawan = 7x = 7 * 6 =42
and that of sushil = 2x = 2 * 6 = 12...
thnx...maybe this is helpful.. :0
Anonymous:
thnx navya.. :)
Answered by
23
Here is your solution
Given :-
ratio of the present age of pawan and sushil is 7:2
After 8 year it becomes ratio 5:2
present age of pawan and sushil is 7x and 2x
A/q
Hence
present age of pawan =7x=7×6=42 years
present age of sushil =2x=2×6=12 years
Hope it helps you
Given :-
ratio of the present age of pawan and sushil is 7:2
After 8 year it becomes ratio 5:2
present age of pawan and sushil is 7x and 2x
A/q
Hence
present age of pawan =7x=7×6=42 years
present age of sushil =2x=2×6=12 years
Hope it helps you
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