Question

The ratio of the present ages of the father and son is 7:2. After 5 years, the
ratio of their ages would be 8: 3. Find their present ages.
​

Answer 1

Answer:

father- 35 years, son- 10 years

Step-by-step explanation:

Let the common multiple of the ratio be x

then the present ages of the father and son respectively will be 7x and 2x

their ages after 5 years respectively will be 7x+5 and 2x+5

as 7x+5 = 8 and 2x+5 = 3, we get the equation =>

$\frac{7x+5}{2x+5}$ = $\frac{8}{3}$

by cross multiplication-

8[2x+5]  = 3[7x+5]

16x+40 = 21x+15

transposing 16x to RHS and 15 to LHS

21x-16x = 40-15

5x = 25

transposing 5 to RHS

x = 25/5

x= 5

as the present ages are 7x and 2x,

the ages are =>

father- 7 x 5 = 35 years

son- 2 x 5 = 10 years

HOPE IT  HELPS, COZ I AM NOT VERY GOOD AT EXPLAINING...

PLS DECLARE BRAINLIEST