Question

The ratio of the sides of a rectangle is 3:5 and it's area is 240 square units, find the perimetr of the rectangle

Answer 1

Answer:

2( 12+20) =64 Square units

Step-by-step explanation:

Ratio of sides =3:5

Let side 'a' =3x

Let side 'b'=5x

Area of a rectangle =ab

But the area of given rectangle =240square units

=>5x * 3x =240

=> 15x^2=240

=>x^2 = 240*1/15

=> x^2 = 16

=> x = 4

1. 3x = 3*4=12 =a

2. 5x=5*4=20 = b

Now perimeter of a rectangle = 2(a+b) So, perimeter of given rectangle =2( 12+20) =2*32=64 square units.

Answer 2

Answer:

Let, the length of the rectangle be, 3x

Then, the breadth of the rectangle, 5x.

It is Given that,

Area of Rectangle =3 : 5 cm.

We know that,

Area of the rectangle , 240 cm

As We know that,

Area of the rectangle = length × breadth

Substituting the values in the above formula, we get,

240 = 2(3x + 5x)

240 = 2 × 8x

.

240 = 16x

x = 240/16

x = 15

Therefore, We got the value off x, 15 cm

Hence,

The length of the rectangle, 3x = 3 × 15 = 45 cm

Then, the breadth of the rectangle, 5x. = 5 × 15 = 80 years.