The ratio of the speed of a projectile at the pt of projection to the speed at the top of ots trajectory is x the angle of projection with the borizontal is
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Let the angle of projection be @
velocity at pt. of projection = u
velocity at top = v
We know that during projectile motion the horizontal velocity of the projectile remains constant
so,
u cos@ = v
u/v = sec@
sec@ =x --------(i)
@ = sec^-1 x
U can convert (i) in sin , cos or tan to get the angle in required form....
velocity at pt. of projection = u
velocity at top = v
We know that during projectile motion the horizontal velocity of the projectile remains constant
so,
u cos@ = v
u/v = sec@
sec@ =x --------(i)
@ = sec^-1 x
U can convert (i) in sin , cos or tan to get the angle in required form....
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