The sum of q terms of an AP is 162.The ratio of its 6th term to its 13th term is 1:2. Find the first and 15th term.
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u r right their is something wrong in this question
The data is insufficient. The q should be replaced with 9
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sum of 9 terms = [2 a + 8 d] 9/2 = 162
a + 4 d = 18 --- (1)
T6/T13 = [a + 5d ] / [a + 12 d] = 1/2
a + 12 d = 2 a + 10 d
a = 2 d
From (1): 6d = 18 => d = 3
so a = 6
T1 = a = 6, T15 = a + 14 d = 48
a + 4 d = 18 --- (1)
T6/T13 = [a + 5d ] / [a + 12 d] = 1/2
a + 12 d = 2 a + 10 d
a = 2 d
From (1): 6d = 18 => d = 3
so a = 6
T1 = a = 6, T15 = a + 14 d = 48
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