The ratio of the speed of two trains A and B running in the opposite direction is 5 : 15 . If each train is 200 m long and crosses each other in 10 s, then find the amount of time (in seconds) that train A takes to cross a man standing on a platform.
Answers
Since The ratio of the speed of two trains A and B running in the opposite direction is 5 : 15
Let the speed of the two trains be
5x m/s and 15x m/s respectively
Since they are running in the opposite direction
So they travels in 1 sec = ( 5x + 15x ) = 20x m
Now each train is 200 m long and crosses each other in 10 s
So in order to cross each other they to cover a distance of ( 200 + 200) m = 400 m
So the required time to cross each other
So according to the given condition
So the speed of the train A is
In order to cross a man sitting in the platform by the train A the train has to travel the length itself
So the required time is
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If a : b=c:d=e: f= 2:1 then (a + 2c + 3e) : (5b + 10d + 15f ) = ?
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Step-by-step explanation:
answer your question is .. 20