Question

The ratio of the sum of money in 3 bags A,B and c is 4:3:2 if 50 is added to each of the bags the ratio becomes 14:13:12. Find the some of money in each of the bags

Answer 1

Solutions :-

Given :
The ratio of the sum of money in 3 bags A, B and C is 4 : 3 : 2
If 50 is added to each of the bags the ratio becomes 14 : 13 : 12.

Let the sum of money in 3 bags A, B and C be 4x, 3x and 2x respectively.


According to the question,

=> (4x + 50) : (3x + 50) : (2x + 50) = 14 : 13 : 12
=> 13(4x + 50) = 14(3x + 50)
=> 52x + 650 = 42x + 700
=> 52x - 42x = 700 - 650
=> 10x = 50
=> x = 50/10 = 5


Therefore,
The amount in the bag A = 4x = 4 × 5 = 20
The amount in the bag B = 3x = 3 × 5 = 15
The amount in the bag C = 2x = 2 × 5 = 10

Answer 2

Solution:

Here, The sum of money in 3 bags A , B & C are in the ratio 4 : 3 : 2.

When 50 is added to each bags , The new ratio becomes 14 : 13 : 12.

Let, The required sum of money in each of the bags be 4k , 3k and 2k respectively.

According To The Condition,

⇒ 4k+50 : 3k+50 : 2k+50 = 14 : 13 : 12
⇒ 13 (4k + 50) = 14 (3k + 50)
⇒ 52k + 650 = 42k + 700
⇒ 50k - 42k = 700 - 650
⇒ 8k = 50
⇒ k = 50 / 8
⇒ k = 5

Similarly,
Sum of money in Bag A = 4k = 4 × 5 = 20
Sum of money in Bag B = 3k = 3 × 5 = 15
Sum of money in Bag C = 2k = 2 × 5 = 10

Hence,
The Required sum of money in 3 bags A , B & C are 20 , 15 and 10 respectively.