Question

The ratio of the sum of n terms of two ap is 3n - 13 and 5n + 21 the ratio of 24th term is

Answer 1

Answer:

solved

Step-by-step explanation:

S1 = n/2(a+U1)

S2 = n/2(a+U2)

(a+U1) /(a+U2) =  3n - 13 / 5n + 21

(a+U1) ( 5n + 21  ) = (a+U2) ( 3n - 13   )

( 5n + 21  )a +  ( 5n + 21  )U1 =  ( 3n - 13   ) a +  ( 3n - 13   ) U2

( 2n +34  ) a + ( 5n + 21  )U1 =    ( 3n - 13   ) U2

( 2n +34  ) a + ( 5n + 21  )(a + (n-1)d1) =    ( 3n - 13   ) (a + (n-1)d2)

( 2n +34  ) a/(a + (n-1)d1) + ( 5n + 21)   =    ( 3n - 13   ) (a + (n-1)d2)/ )(a + (n-1)d1)