the ratio of the sums of 1st m and n terms of an AP is m^2:n^2 Show that the ratio of its mth and nth term is (2m-1):(2n-1)
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The sum of 1st n odd numbers =n^2
The sum of 1st m odd numbers=m^2
So for any A.P IN the form of odd numbers the last term is 2n-1 or 2m-1
So the ratio of nth and mth terms = (2n-1):(2m-1)
The sum of 1st m odd numbers=m^2
So for any A.P IN the form of odd numbers the last term is 2n-1 or 2m-1
So the ratio of nth and mth terms = (2n-1):(2m-1)
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