The ratio of the third and 6th term of an arithmetic sequence is 4 : 5.
a. Find the ratio of 7th and 11
th terms.
b. If the 11
th term is 60, then find its 16th term.
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Answer:
a)4:5
b)75
a)take the ratio of third term and sixth term = 4/5
now from that eqn find a=10d.
now put that in the eqn of a+6d
a+10d
and find the ration 16d/20d = 4/5
b) a + 10d = 60
10d+10d = 60
d= 3
now and a = 30
a+15d = 30+15*3=75.
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