The ratio of the torsional moments of resistance of a solid circular shaft of diameter d, and a hollow circular shaft having external diameter d and internal diameter d is given by
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The strength of a solid shaft in torsion is given by,
T(solid shaft) = (pi/16)*(max stres)*(D^3).
T(hollow shaft) = (pi/16)*(max stres)*(D^4-d^4)/D.
On solving we get 15/16.
T(solid shaft) = (pi/16)*(max stres)*(D^3).
T(hollow shaft) = (pi/16)*(max stres)*(D^4-d^4)/D.
On solving we get 15/16.
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