The ratio of the two charges is 2: 3 and the distance between them is 5cm.If the value of the active ball between them is 96dyn then what is the value of the two charges
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Answer:
13.32nc,19.98nc
Explanation:
Given the magnitude of charges=2x and 3x respectively
distance d=5cm
Force=96dyne
x=6.66nc(By calculations)
3x=19.98nc
2x=13.32nc
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