Question

the ratio of the volume of two drops of the same liquid is 1:8 the excess pressure inside the drops will be in the ratio of​

Answer 1

The ratio of excess pressure inside the drops

= 2:1

Given:

The ratio of the volume of two drops of the same liquid is 1:8.

To find:

The excess pressure inside the drops will be in the ratio of​.

Formula used:

volume of sphere = $\frac{4}{3} \times \pi \times r^{3}$

Excess pr. inside the liquid drop = $\frac{2 \sigma}{r}$

                 Where $\sigma$ = Surface tension

                             d= diameter of drop

Explanation:

• volume of sphere = $\frac{4}{3} \times \pi \times r^{3}$
• ( $\frac{4}{3} \times \pi$) is constant term so
• Volume of sphere ∝ r³
• The ratio of the volume of two drops of the same liquid is 1:8.
• So ratio of radius of the drop = $\sqrt[3]{1:8}$ = 1:2
• Excess pr. inside the liquid drop = $\frac{2 \sigma}{r}$
• From this equation it is clear that Excess pr. inside the liquid drop  ∝ $\frac{1}{r}$
• So the ratio of excess pressure inside the drops = 2:1

To learn more....

1 Problem 4. (a) Surface tension of soap solution is 0.072

N/m. How much work is done in blowing a soap bubble of

radius1/3√π ?

(b) How much work is done to form an air bubble of

radius 1/3√π inside the solution?

https://brainly.in/question/13854924

2 The charge in surface energy when a drop of radius R splits into 8 droplets, each of radius r is (surface tension is T)

https://brainly.in/question/9473996