Math, asked by harshit9434, 1 year ago

the ratio of two adjacent sides of a parallelogram is 2:3 it's perimeter is 50cm find its area if altitude corresponding to larger side is 10 cm

Answers

Answered by AlexaRousey
33
#AlexaRousey here!!

Let the meet of ratio be x.

Since Perimeter of llgm = 2(l+b)

=) 50cm = 2(3x+2x)

=) 50cm = 10x

=) 50/10 = 5cm = x

Hence sides are 2*5cm nd 3*5cm = 10cm nd 15cm.

Since area of llgm = base* height

= 15cm(larger side) * 10cm

= 150cm^2

Thanks!!

harshit9434: thnq
Answered by Anonymous
9
given the ratio between the two adjacent sides if the parallelogram is 2 : 3

let the adjacent sides of the parallelogram be 2x and 3x.

we know the formula for solving for the perimeter of a parallelogram is 2 ( l + b ) where l and b are the adjacent sides of the parallelogram.

therefore 2 ( l + b ) = 50cm

==> 2 ( 2x + 3x ) = 50cm

==> 2x + 3x = 50/2

==> 5x = 25cm

==> x = 25/5

==> x = 5

hence, the Length of the adjacent sides of the parallelogram are :-

2x = 2 × 5 = 10cm

and

3x = 3 × 5 = 15cm

now, we have to find the area of the parallelogram where the height (altitude) is corresponding to the larger side.

here the larger side is 15cm.

therefore the base is 15cm and height = 10cm

area of the parallelogram = base × height

= 15 × 10

= 150cm²

HOPE THIS HELPS..!!
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