Question

. The ratio of two supplementary angles is 4 : 5. Find both angles.​

Answer 1

$\huge\rm\red{Answer☟︎︎︎ }$

Let two angles be 4x and 5x

➪ Sum of supplementary angles is 180⁰

➪ ∴4x+5x=180⁰

➪ 9x=180⁰

➪ x= 180/90 =20⁰

➪ So, one angle = 4x=4×20=80⁰

➪ Another angle = 5x=5×20=100⁰

➪ Larger of two angle is 100⁰

Answer 2

Answer:

>> Given -:

$\textsf{Ratio of two supplementary angle = 4:5}$

$\textsf{Supplementary angle = 180°}$

>> To find -:

$\textsf{Find both angles}$

>> Taken -:

To find the angles:

Let the 4:5 be 4x and 5x

$\bold{\boxed{R=S}}$

Where,

R = Sum of the ratio

S = Supplementary angle

>> Concept -:

Just do sum of both the ratio as x . Then , divide .

At last multiply the angle which has been come by dividing with both the ratio . Then , the angles of both the ratio will come .

>> Calculation -:

$\implies{4x+5x=180°}$

$\implies{9x=180°}$

$\implies{x=180°/9}$

$\implies{x=20°}$

$\dag$ Angles of the ratio:

$\implies{4×20°=80°}$

$\implies{5×20°=100°}$

>> Verification -:

To verify do sum of both the angles . If the total sum will come 180° . Then , the answer will be verified.

$\implies{80°+100°}$

$\implies{180°}$

Hence , the answer is verified .

>> Answer -:

So , the ratio 4:5 are in the angles of 80° and 100° respectively.

>> Extra information -:

To find area of the triangle :

$At=\frac{H×B}{2}$

Where,

At = Area of the triangle

H = Height

B = Base

To find velocity :

$Velocity=\frac{Displacement}{Time}$

To find Acceleration :

$A=\frac{V1-V}{T}$

Where,

A = Acceleration

V1 = Final velocity

V = Initial velocity

T = Time