the ratio of velocities of particle in SHM at displacements A/3 and 2A/3 is
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Answer:
Velocity of a particle executing S.H.M. is given by
v=ω
A62−x
2
ω=
T
2π
Here x = A/3 and 2A/3
when displacement is A/3
v=
T
2π
A
2
−(
3
A
)
2
v=
T
2π
3
A
8
when displacement is 2A/3
v
′
=
T
2π
A
2
−(
3
2A
)
2
v
′
=
T
2π
3
A
5
So
v
′
v
=
5
8
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