The ratio of velocity of an electron in the first three Bohr's
orbit of hydrogen atom is
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Explanation:
ANSWER
In hydrogen atom the speed of electron is v=
2ε
0
nh
e
2
........(1)
Where, e is the charge of electron
n = 1 as first orbit
Dividing equation (1) by c
c
v
=
2ε
0
ch
e
2
c
v
=
2×8.85×10
−12
×3×10
8
×6.6×10
−34
(1.6×10
−19
)
2
c = 137
-------
v 1
Ratio is 1 : 137
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