Question

The ratio of velocity of the electron of H atom in two of the first six orbits n, and n, is 1: 3. The dn₂ difference between potential energy of electron in the two orbits n, and n, i.e. (PE-PE,2) can be


(1) Either-12.09 eV or-3.02 eV

(2) Either 24.18 eV or 6.04 eV

(3) Either 12.09 eV or 3.02 eV

(4) Either-24.18 eV or-6.04 eV​

Answer 1

Answer:

6xy+−7xy+9xy+−3xy

Combine 6xy and −7xy to get −xy.

−xy+9xy−3xy

Combine −xy and 9xy to get 8xy.

8xy−3xy

Combine 8xy and −3xy to get 5xy.

5xy