Question

The ratio of water and alcohol in two different containers is 2:3 and 4:5. In what ratio we are required to mix the mixtures of two containers in order to get the new mixture in which the ratio of alcohol and water be 7:5?
A) 7:3
B) 5:3
C) 8:5
D) 2:7

Answer 1

its anawwe is c option is write

Answer 2

The ratio of water and alcohol in two different containers is 2:3 and 4:5. In what ratio we are required to mix the mixtures  of two containers in order to get the new mixture in which the ratio of alcohol and water be 7:5?

A) 7:3
B) 5:3
C) 8:5
D) 2:7

ĀNSWĒR ⏬⏬  
 B) 5:3 

Explanation:

W1:A1  W2:A2  ..... WN:ANW1:A1  W2:A2  ..... WN:AN

  2 : 3                   4 : 5                    5 : 7 

 

W1/W1+A1 = 25 W2/W2+A2=49  WN/WN+AN = 512W1W1+A1 = 25 W2W2+A2=49  WNWN+AN = 5/12

= 72/180

= 80/180

= 75/180  

                     

 =>     5   :   3


Therefore, the ratio is  5: 3
THANKS ✌✌

# NAVI ❤ HARYANVI ♠