Question

The ratio of weights of tin and zinc in an alloy is 2:5. How much zinc is there in
31.5 g of alloy?
​

Answer 1

Answer:

• 9 grams of zinc is there in the alloy.

Given:

• Ratio of zinc and tin in the alloy = 2:5
• Total weight of alloy = 31.5 g

To find:

• How much zinc is there in 31.5 g of alloy?

Solution:

Weight of tin = 2x

Weight of zinc = 5x

➨ Zinc + Tin = Alloy

By replacing the data given to us, We get:

➨ 2x + 5x = 31.5

➨ 7x = 31.5

➨ x = $\bf \dfrac{31.5}{7}$

➨ x = 4.5 grams.

Thus,

Weight of zinc = 2x = 9 grams.

• 2 × 4.5 = 9 grams.

Weight of tin = 5x = 22.5 grams.

• 5 × 4.5 = 22.5 grams.

Hence, 9 grams of zinc is there in the alloy.

Answer 2

Correct Question-:

• The ratio of weights of tin and zinc in an alloy is 2:5. How much zinc is there in
• zinc is there in31.5 g of alloy?

AnswEr -:

• $\underline{\boxed{\star{\sf{\blue{Weight \: of\: Zinc\: = 9 gm }}}}}$

EXPLANATION-:

• $\frak{Given \:\: -:} \begin{cases} \sf{ The\: ratio\: of \:weights\: of \:tin\: and\: zinc\: in\: an\: alloy\: is\: 2:5. } & \\\\ \sf{The\:Weight\:of\:an\;alloy=31.5g }\end{cases}$

• $\frak{To \:Find\: -:} \begin{cases} \sf{ The\: weight\:of\:zinc\:in\:an\:alloy.}\end{cases}$

Solution-:

$\frak{ Let's \:Assume \:\: -:} \begin{cases} \sf{Let \:the\: weight\: of \:tin \:be\: 5x. } & \\\\ \sf{Let\:the\:Weight\:of\:an\;zinc\:be\:2x }\end{cases}$

Now ,

• As ,we know that ,

• "Weight of Tin + Weight of Zinc = Weight of an alloy ."

• $\frak{ \: Here \:\: -:} \begin{cases} \sf{The\: weight\: of \:tin \:is\: 2x. } & \\\\ \sf{\:The\:Weight\:of\:an\;zinc\:is\:5x } & \\\\ \sf{ The\:weight \:of\:an\:alloy\:is\:31.5gm}\end{cases}$

Now ,

• $\implies{\sf{\large { 5x + 2x = 31.5gm }}}$
• $\implies{\sf{\large { 7x = 31.5gm }}}$
• $\implies{\sf{\large { x = \frac{31.5}{7} }}}$
• $\implies{\sf{\large { x = 4.5gm }}}$

Therefore-:

• $\underline{\boxed{\star{\sf{\blue{ x = 4.5 gm }}}}}$

Then ,

• $\implies{\sf{\large { Weight \: of\: Zinc = 2x = 4.5 × 2 = 9gm }}}$
• $\implies{\sf{\large { Weight \: of\: Tin = 5x = 4.5 × 5 = 22.5gm }}}$

Hence ,

• $\underline{\boxed{\star{\sf{\blue{Weight \: of\:Zinc\: = 9 gm }}}}}$

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