Math, asked by ajay9093, 1 year ago

the ratio pf ages of ravi 5 years ago and that of rohans age after 5 years is 2:3 .the ratio of their present age is 3:4.what is the age of ravi before 3 years and that of rohans age after 7 years?

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Answered by rakeshmohata
4
Hope u like my process
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Ratio of their present age = 3:4

Let the common ratio be x years

The present age of Ravi = 3x years.

The present age of Rohan = 4x years

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Age of Ravi 5 years ago = (3x - 5) years

Age of Rohan 5 years later=(4x+5) years

It's ratio = 2:3

By problem,
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 =  >  \frac{(3x - 5)}{(4x + 5)}  =  \frac{2}{3}  \\  \\ or. \:  \: 3(3x - 5) = 2(4x  + 5) \\  \\ or. \:  \: 9x - 15 = 8x + 10 \\  \\ or. \:  \: 9x - 8x = 10 + 15 \\  \\ or. \:  \: x = 25 \:  \:  \: \:
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So,

Ravi's age before 3 years =(3x-3)

=(3×25 - 3) = (75 - 3) = 72 years

Rohan's age after 7 years = (4x +7)

= (4×25 +7) = 107 years

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So the required ratio = 72/107

=72 : 107 __(answer)

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